5v^2+35v+60=0

Solution for 5v^2+35v+60=0 equation:

5v^2+35v+60=0

a = 5; b = 35; c = +60;
Δ = b2-4ac
Δ = 352-4·5·60
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-5}{2*5}=\frac{-40}{10}
=-4
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+5}{2*5}=\frac{-30}{10}
=-3
$